Stable populations based on a life table and assumed growth rate (cont.)
Constructing a stable population from a stationary (life table) population and an assumed growth rate
We will construct a stable population with growth rate 3% from a stationary population based on the following life table, based on a radix of 1000 births:
age group a to a+n ![]() |
nLa |
---|---|
0 – 5 | 700 ![]() |
5 – 10 | 500 |
10 – 15 | 300 |
15 – 20 | 200 |
20 – 25 | 100 |
25 – 30 | 0 |
total person-years lived in stationary population | 1800 |
If the population is growing at 3% per year, and there were 1,000 births in the base year,
then the following year the number of births will be 1,000 x exp(0.03) = 1,000 x 1.03 = 1,030,
and 5 years later, the number of births will be 1,000 x exp{0.03 x 5} = 1,000 x 1.162 = 1162
whereas the number of births in the year before the base year was 1,000 x exp{-0.03} = 970,
similarly the number of births 15 years earlier was 1,000 x exp{-0.03 x15} = 638.
The next table shows how the relative size of the birth cohorts born Y years before the base year is calculated, and then derives the number of survivors at each age group in the stable population.
age group a to a+n | nLa | survivors born on average Y years earlier | relative size of birth cohort born Y years earlier exp{-0.03 x Y} | stable population age group a to a+n nLa x exp{-0.03 x Y} | proportion aged a to a+n in stable population |
---|---|---|---|---|---|
0 – 5 | 700 | 2.5 | 0.928 | 649 | 45.6% |
5 – 10 | 500 | 7.5 | 0.799 | 399 | 28.0% |
10 – 15 | 300 | 12.5 | 0.687 | 206 | 14.5% |
15 – 20 | 200 | 17.5 | 0.592 | 118 | 8.3% |
20 – 25 | 100 | 22.5 | 0.509 | 51 | 3.6% |
25 – 30 | 0 | 27.5 | |||
stable population total | 1,424 | 100.0% |
For example those aged 10-15 will have been born on average 12.5 years ago, so that their birth cohort was exp{-0.03 x 12.5} = 0.687 times smaller than the cohort born in the base year. Since 300 of 1000 births survive to ages 10-15, the stable population aged 10-15 is 300 x 0.687 = 206